Question #58265

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Answer 1 · 2017-03-18T16:53:22

#tanx=(opposite)/(adjacent)=5#

#color(red)(Cotx=0.2# , #color(red)(tanx?#

In a right #triangle# there is a slope side-hypotenuse,
opposite side and adjacent side.

#:.cotx=0.2=1/5#

#:.cotx=(adjacent)/(opposite)# ,#adjacent=1# #opposite=5#

#:.tanx=(opposite)/(adjacent)#

#:.tanx=5/1#

#:.color(red)(tanx=5#

on calculator:

#:.arctan(tan^-1)0.2=11.30993247°=11°18'35.7''#

#:.tan11.30993247=0.199999713# #=0.2 #to the nearest 1 decimal

#:.0.199999713 1/x =5.000007173= cotx#