How do you divide (4p ^ { 3} q ^ { 5} ) ^ { 0} \div ( 6p ^ { 2} ) ^ { - 1}?

2 Answers
Mar 18, 2017

6p^2

Explanation:

Any number to the 0 power is equal to 1

(4p^3q^5)^0 = 1

Distribute the -1 to 6 and p^2

1/((6^-1)(p^(2(-1)))) = 1/((6^-1)(p^-2))

Any number to a negative exponent is equal to its reciprocal
For example: a^-2 = 1/(a^2)

1/((6^-1)(p^-2))= 6p^2

ANSWER: 6p^2

Mar 18, 2017

6p^2

Explanation:

I have used substitutions a and b to demonstrate what is happening to groups. I do this in an attempt reduce confusion about the action of mathematical processes

Set a=4p^3q^5 so that we have a^0

But a^0=1 so (4p^3q^5)^0=1

Now we have: 1-:(6p^2)^(-1)

Set b=(6p^2)^(-1)

1-:b" "=" " 1xx1/b

=1xx1/((6p^2)^(-1)

=1xx6p^2

=6p^2