How do you solve #(2x-5)/4-x/3=2-(x+4)/6#?

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Answer 1 · 2017-03-19T18:36:11

#"answer : "x=31/4#

#(2x-5)/4-x/3=2-(x+4)/6#

#color(red)(3/3)*(2x-5)/4-color(blue)(4/4)*x/3=color(green)(12/12)*2-color(cyan)(2/2) (x+4)/6#

#(3(2x-5))/12-(4x)/12=24/12-(2(x+4))/12#

#(3(2x-5)-4x)/12=(24-2(x+4))/12#

#(3(2x-5)-4x)/cancel(12)=(24-2(x+4))/cancel(12)#

#3(2x-5)-4x=24-2(x+4)#

#cancel(6x)-15-cancel(4x)=24-2x-8#

#2x-15=16-2x#

#2x+2x=16+15#

#4x=31#

#(cancel(4)x)/cancel(4)=31/4#

#x=31/4#