How do you solve $-2abs(y-7)+18=8$ ?

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Answer 1 · 2017-03-20T05:10:31

$y = 12$ or $y = 2$

First subtract $18$ from both sides
$-2abs(y-7) = 8-18$
$-2abs(y-7) = -10$

Then divide both sides by $-2$
$abs(y-7) = 5$

Since $abs(y-7) = 5$
$y-7 = 5$ or $y-7 = -5$
$y = 5+7$ or $y = -5+7$
$y = 12$ or $y = 2$

How do you solve -2abs(y-7)+18=8-2abs(y-7)+18=8?