How do you find the quotient of #(3x^2 + 4xy + 3xy + 4y^2) ÷ (x + y)#?

2 Answers
Mar 20, 2017

The remainder is #=0# and the quotient is #color(red)(=3x+4y#

Explanation:

# color(white)(aaaaaaa)##color(red)(3x+4y#
#color(white)(aaaaaa)##-----#
#color(white)(aaaaa)##|##3x^2+7xy +4y^2#
#color(white)(aaaaaaaaaaaa)##3x^2+3xy#
#color(white)(aaaaaaaaaaaaa)##0+4xy+4y^2#
#color(white)(aaaaaaaaaaaaaaaa)##4xy+4y^2#
#color(white)(aaaaaaaaaaaaaaaaa)##---#
#color(white)(aaaaaaaaaaaaaaaaaaa)##0+0#

The remainder is #=0# and the quotient is #color(red)(=3x+4y#

Mar 20, 2017

#" The Quotient="(3x+4y).#

Explanation:

#ul(3x^2+4xy)+ul(3xy+4y^2),#

#=x(3x+4y)+y(3x+4y),#

#=(3x+4y)(x+y).#

#:. (3x^2+4xy+3xy+4y^2) -: (x+y),#

#=(3x^2+4xy+3xy+4y^2)/(x+y),#

#={(3x+4y)(cancel(x+y))}/(cancel(x+y)),#

#=(3x+4y)," is the desired quotient."#

Enjoy Maths.!