How do you solve the system of equations #2x + 4y = - 2# and #3x + 4y = 1#?

1 Answer
Cri007
Mar 20, 2017

See below.

Explanation:

Since the number in front of the #y#'s in the two equation are the same, it is best to you elimination. Let's just subtract the two equations.

#2x+4y=-2#
#-#
#3x+4y=1#

So,
#-x=-3#, or #x=3#.

Plugging this into the first equation,

#2(3)+4y=-2#
#4y=-2-6=-8#, so #y=-2#.

So the solution to this system is #(3, -2)#.

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