Question

Question #9a852

Answer 1

`2sin²x-3sinx + 1 = 0`

`=>2sin²x-2sinx-sinx + 1 = 0`

`=>2sinx(sinx-1)-(sinx - 1) = 0`

`=>(sinx-1)(2sinx - 1) = 0`

when

`sinx-1=0`

`=>sinx=1=sin(pi/2)`

`=>x= npi+(-1)^npi/2" where " n in ZZ`

when

`2sinx-1=0`

`=>sinx=1/2=sin(pi/6)`

`=>x= npi+(-1)^npi/6" where " n in ZZ`