How do you solve #-14- 4x = 14- 3x#?

2 Answers
Mar 22, 2017

#x=-28#

Explanation:

Collect terms in x on the left side of the equation and numeric values on the right side.

add 3x to both sides.

#-14-4x+3x=14cancel(-3x)cancel(+3x)#

#rArr-14-x=14#

add 14 to both sides.

#cancel(-14)cancel(+14)-x=14+14#

#rArr-x=28#

multiply both sides by - 1

#(-1xx-x)=(-1xx28)#

#rArrx=-28#

#color(blue)"As a check"#

Substitute this value into the equation and if the left side equals the right side then it is the solution.

#"left side "=-14-(4xx-28)=-14+112=98#

#"right side "=14-(3xx-28)=14+84=98#

#rArrx=-28" is the solution"#

Mar 22, 2017

#x=-28#

Explanation:

#-14-4x=14-3x#

#:.-4x=14-3x+14#

multiply L.H.S. and R.H.S. by -1

#:.4x=-14+3x-14#

#:.4x-3x=-14-14#

#:.x=-28#