How do you factor #x^ { 2} + 23x= 188#?

1 Answer
Smitty123
Mar 23, 2017

This is your answer. #x=(-23+- sqrt1281)/2#

Explanation:

You will have to use the quadratic formula. #(-b +- sqrt (b^2-4ac))/(2*a) #. plug in 23 for b, 1 for a, and -188 for c. #23^2=529#. so #-23/((2)(1))+-sqrt ( (-23)^2-(4)(1)(-188))/((2)(1))# simplify everything and

you get #x=(-23+- sqrt1281)/2# .

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