Question

Question #88dab

Answer 1

The magnetic field wil halved.

Explanation:

At the center of the loop, the magnetic field is given by

`B=(mu_o I)/(2r)`

Where

the radius `=r`

and the diameter is `d=2r`

So,

`B=(mu_o I)/(d)`

If we double `d`, that is

`D=2d`

Then,

`B_1=(mu_o I)/(D)=(mu_o I)/(2d)=B/2`

Therefore,

The magnetic field wil be half the value