How do you solve #x^{2}+(x-3)^{2}=225#?

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Answer 1 · 2017-03-25T09:01:39

#"answer x=12 or x=-9"#

#x^2+(x-3)^2=225#

#"please note that "(x-y)^2=x^2-2xy+y^2#

#(x-3)^2=x^2-6x+9#

#x^2+(x^2-6x+9)=225#

#x^2+x^2-6x+9=225#

#2x^2-6x+9-225=0#

#2x^2-6x-216=0 " if we simplify , we obtain the equation below."#

#x^2-3x-108=0#

#"Now ,let us factor the equation above".#

#(x+9)(x-12)=0#

#"if "(x+9)=0" than "x=-9#

#"if "(x-12)=0" than "x=12#