How do you graph the equation #y=x+5#?
1 Answer
Mar 25, 2017
see explanation.
Explanation:
The equation of a line in
#color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b. the y-intercept.
#y=x+5" is in this form"#
#rArr(0,5)color(red)" is a point on the graph"# To draw a line we require 2 points.
Choose any value of x to obtain a second point.
#x=3toy=3+5=8#
#rArr(3,8)color(red)" is a point on the graph"# Plot these 2 points and draw a straight line through them and you have the graph.
graph{x+5 [-11.24, 11.27, -5.63, 5.61]}