In the equation #y=-x-5#, what is #y# equal to when #x=4#?

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Answer 1 · 2017-03-26T13:22:34

See the solution process below:

To solve this we must substitute #color(red)(4)# for #color(red)(x)# in the equation and calculate #y#:

#y = -color(red)(x) - 5# becomes:

#y = -color(red)(4) - 5#

#y = -9#

Answer 2 · 2017-03-26T13:49:44

#y=-9#

#color(blue)(y=-x-5#

We know that #x=4#

So, substitute it into the equation

#rarry=-4-5#

#rArrcolor(green)(y=-9#

Hope this helps :)