How do you simplify #(\frac { u ^ { 3} v ^ { - 1} } { 2w ^ { 3} } ) ^ { - 3} ( u w ^ { 3} )#?

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Answer 1 · 2017-03-27T04:32:00

#(8v^3w^12)/u^8#

Since #(a^b)^c=a^(bc)#, you get:

#(u^-9v^3)/(2^-3w^-9)*uw^3#;

since #a^b*a^c=a^(b+c)#, you get:

#(u^-8v^3w^3)/(2^-3w^-9)#;

since #a^b/a^c=a^(b-c)#, you get:

#(u^-8v^3w^12)/2^-3#;

since #a^-b=1/a^b#, you get:

#(2^3v^3w^12)/u^8#

#=(8v^3w^12)/u^8#