Question

How do you find the product of `(w+4)(w^2+3w-6)`?

Answer 1

`(w+4)(w^2+3w-6)=w^3+7w^2+6w-24`

Explanation:

We use distributive property i.e. multiplying `(w^2+3w-6)` first by `w` and then by `4` and then adding the two.

`(w+4)(w^2+3w-6)`

= `w(w^2+3w-6)+4(w^2+3w-6)`

= `wxxw^2+wxx3w-wxx6+4xxw^2+4xx3w-4xx6`

= `w^3+3w^2-6w+4w^2+12w-24`

= `w^3+7w^2+6w-24`