Question #50ca2

1 Answer
Mar 27, 2017

cosθ1sinθ=secθ+tanθ

Explanation:

Start from the first member:

cosθ1sinθ

multiply and divide by (1+sinθ):

cosθ1sinθ=cosθ1sinθ1+sinθ1+sinθ

cosθ1sinθ=cosθ1+sinθ1sin2θ

cosθ1sinθ=cosθ1+sinθcos2θ

cosθ1sinθ=1+sinθcosθ

cosθ1sinθ=1cosθ+sinθcosθ

cosθ1sinθ=secθ+tanθ