Question

How do you multiply `(\frac { 1} { 3} x ^ { 2} - 8) ( \frac { 1} { 3} x ^ { 2} + 8)`?

Answer 1

`1/9x^4-64`

Explanation:

Let's apply the formula:

`(a-b)(a+b)=a^2-b^2`

Then you would get:

`(1/3x^2-8)(1/3x^2+8)=1/9x^4-64`