A circle has center at #(0,0)# and passes through #(-12,0)#, what is its circumference and area?

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Answer 1 · 2017-03-30T05:25:18

Circumference is #24pi# and area is #144pi#

As the circle has center at #(0,0)# and passes through #(-12,0)#, its radius is

distance between #(0,0)# and #(-12,0)#

i.e. #sqrt((-12-0)^2+(0-0)^2)=sqrt(144+0)=12#

As radius is #12#,

Circumference is #2xxpixxr=2pixx12=24pi#

and area is #pixx12^2=pixx144=144pi#

Answer 2 · 2017-03-30T12:30:28

#24pi,# #144pi#

#color(blue)((0,0)and(-12,0)#

The distance between these points is the radius of the circle

#color(brown)("Distance"=sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

#rarrsqrt((-12-0)^2+(0-0)^2)#

#rarrsqrt(144)#

#color(green)(rArr12#

We know the radius, let's find the circumference

#color(brown)("Circumference"=2pir#

#rarr2*pi*12#

#rarr528/7#

#color(green)(rArr24pi#

Now find the area

#color(brown)("Area"=pir^2#

#rarrpi*12^2#

#color(green)(rArr144pi#

Hope this helps...:)