A #16g# mass of sodium hydroxide is dissolved in enough water to give #2.0L# of solution. What is the concentration of the solution in #mol*L^-1#?

Question

1733 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-02T19:40:52

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"=#

#"Molarity"# #=# #((16.0*cancelg)/(40.0*cancelg*mol^-1))/(2.0*L)=0.20*mol*L^-1#.

Note how the units cancel to give the required units of concentration, i.e. #mol*L^-1#:

#((cancelg)/(*cancelg*mol^-1))/(L)=mol*L^-1#, i.e. #1/x^-1# #=# #1/(1/x)# #=# #x# as required...........

A #16*g# mass of sodium hydroxide is dissolved in enough water to give #2.0*L# of solution. What is the concentration of the solution in #mol*L^-1#?