A 30 kg block slides on a frictionless 20° inclined plane A force of 16 N acting parallel to the incline and up the incline is applied to the block. What is the acceleration of the block?

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Answer 1 · 2017-04-03T12:55:29

The block will move down the plane with an acceleration of #=2.82ms^-2#

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Solving in the direction parallel to the plane

#F-Wsintheta=m*a#

#F=16N#

#W=mg=30gN#

The mass is #m=30kg#

The angle is #theta=20º#

So,

#16-30gsin20º=30*a#

#30a=16-100.55=-84.55#

#a=-84.55/30=-2.82ms^-2#