Question

How do you write the quadratic function in standard form `y=-1/2(x-6)(x-8)`?

Answer 1

`7x-x^2/2-24`

Explanation:

Let's first multiply `(x-6)(x-8)`. We will use FOIL to expand this (first, outer, inner, last).

First: `x*x=x^2`
Outer: `x*-8=-8x`
Inner: `x*-6=-6x`
Last: `-8*-6=48`

Add these all up to get `x^2-14x+48`.

Now, don't forget to multiply each of these terms by `-1/2` to get `-x^2/2+7x-24`. We can arrange the terms so that the positive term is in the front `7x-x^2/2-24`.