Question

How do you perform the operation and write the result in standard form given `(3+2i)-(6+13i)`?

Answer 1

Given the difference between complex numbers two,

`(a+bi)-(c+di)`,

the difference is:

`(a - c) + (b - d)i`

Explanation:

Given: `(3+2i)-(6+13i)`

`(3+2i)-(6+13i) = 3-6 + (2 - 13)i`

`(3+2i)-(6+13i) = -3 - 11i`