How do you simplify #(sqrt(x) / (y^-2)) ^4 #?
1 Answer
Apr 4, 2017
Explanation:
To start we can deal with the negative exponent using the rule
#(sqrtx/y^-2)^4=(sqrtx/(1/y^2))^4=(y^2sqrtx)^4#
We should rewrite
#(y^2sqrtx)^4=(y^2x^(1/2))^4#
Split up the exponent:
#(y^2x^(1/2))^4=(y^2)^4(x^(1/2))^4#
Use the rule
#(y^2)^4(x^(1/2))^4=y^(2(4))x^(1/2(4))=x^2y^8#