Question

How do you find the x and y intercepts of `-6x+8y=-36`?

Answer 1

See the entire solution process below:

Explanation:

To find the y-intercept, set `x` to `0` and solve for `y`:

`(-6 xx 0) + 8y = -36`

`0 + 8y = -36`

`8y = -36`

`(8y)/color(red)(8) = -36/color(red)(8)`

`(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) = (4 xx -9)/color(red)(4 xx 2)`

`y = (color(red)(cancel(color(black)(4))) xx -9)/color(red)(color(black)(cancel(color(red)(4))) xx 2)`

`y = -9/2`

The y-intercept is `-9/2` or `(0, -9/2)`

To find the x-intercept, set `y` to `0` and solve for `x`:

`-6x + (8 xx 0) = -36`

`-6x + 0 = -36`

`-6x = -36`

`(-6x)/color(red)(-6) = (-36)/color(red)(-6)`

`(color(red)(cancel(color(black)(-6)))x)/cancel(color(red)(-6)) = 6`

`x = 6`

The x-intercept is `6` or `(6, 0)`