How do you find the zeros of #f(x)=2x^2+x-3#?

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Answer 1 · 2017-04-05T15:42:01

#x_1=1 and x_2=-3/2#

Factor the equation #f(x)# (I'll use decomposition),

#f(x)=2x^2+2x-3x-3#

Factor,

#f(x)=2x(x-1)+3(x-1)#

Simplify,

#f(x)=(2x+3)(x-1)#

Let #f(x)=0,#

#0=(2x+3)(x-1)#

The values of x that make this statement above true (zeros), are

#x_1=1 and x_2=-3/2#