Can someone give me a clue, how can i solve this? I want something like: #x=pi/4+kpi# ---> Solve this: #2sin^2(x)-sin^2(2x)=cos^2(2x)#

#2sin^2(x)-sin^2(2x)=cos^2(2x)#

It should be:

#x=pi/4+kpi# AND #x=(3pi)/4+kpi#