If #f(x)= sqrt(12x+6)/(8x-5)#, what is #f(1/4)#?

1 Answer
Apr 6, 2017

#f(1/4)=color(blue)(-1)#

Explanation:

If #f(color(red)x) =sqrt(12color(red)x+6)/(8color(red)x-5#
then
#color(white)("XXX")f(color(red)(1/4))=sqrt(12 * color(red)(1/4) +6)/(8 * color(red)(1/4)-5)#

#color(white)("XXXXXXX")=sqrt(3+6)/(2-5)#

#color(white)("XXXXXXX")=sqrt(9)/(-3)#

#color(white)("XXXXXXX")=3/(-3)#

#color(white)("XXXXXXX")=-1#