How do you solve #\sqrt { 4x ^ { 2} - 4x - 5} = 2x - 2#?
1 Answer
Apr 7, 2017
See below.
Explanation:
We start by squaring both sides (because no one likes ugly radicals)
Aha! The squared terms cancel!
This simplifies to:
We have to be careful now. The right side of this equation cannot be negative, or else the radical does not result in a real solution (extraneous).
We need