How do you solve #(-4) + 4/(-5z) = -5#?

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Answer 1 · 2017-04-09T05:06:38

#z=4/5#

Given: #(-4)+4/(-5z)=-5#

We can multiply both sides by #-5z# to remove the fraction:

Then: #(-4)+4/(-5z)=-5#

Becomes: #(-4)(-5z)+4=-5(-5z)#

#20z+4=25z#

Subtract #20z# from both sides:

#4=5z#

#z=4/5#

To check, put #z=4/5# into the #given# equation:

#(-4)+4/(-5z)=-5#

#(-4)+4/(-5(4/5))=-5#

#(-4)+4/(-4)=-5#

#(-4)-1=-5#