If f(x)=-(x-4)^2-3f(x)=−(x−4)2−3, on what interval(s) is f(x)f(x) increasing?
2 Answers
Apr 10, 2017
(-infinity, 4)
Explanation:
To know where f(x) is increasing then we need to see where the derivaitve is +
f'(x)=
This hits 0 at x=4
For x<4: the derivative is positive therefore the function is increasing.
For x>4: the derivative is negative therefore decreasing.
So for (-infinity, 4) the function is increasing.
Apr 10, 2017
Explanation:
To determine the interval that f(x) is increasing.
• " increasing when " f'(x) > 0
f'(x)=-2(x-4)larrcolor(red)" using chain rule"
"solve " -2(x-4)> 0
rArr-2x+8>0
rArrx<4
" interval is " (-oo,4)
graph{-(x-4)^2-3 [-8.89, 8.89, -4.445, 4.44]}