Question #b8258

2 Answers
Apr 10, 2017

The question format is not clear.
Quick answer: log of a negative is not permitted so it is a no no to x+4<0x+4<0

Explanation:

NOT MEANT TO BE: (fx)=log_2(x+4)-3(fx)=log2(x+4)3
This would be very different!
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log2log2 would normally be understood as log_10(2)log10(2) which is a constant.

So we have: " "f(x)=log_10(2)(x+4)-3 f(x)=log10(2)(x+4)3

Set: f(x)=y=log(2)x+4log(2)-3f(x)=y=log(2)x+4log(2)3

This is the equation of a strait line

So for this condition we have:

domain (input) ->(-oo,+oo)(,+)
range (output) ->(-oo,+oo)(,+)

However; as there is no 'excluded values' in this it is a little disconcerting that mention is made of an asymptote.

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So perhaps the question is meant to be: (fx)=log_2(x+4)-3(fx)=log2(x+4)3

Set f(x)=y=log_2(x+4)-3f(x)=y=log2(x+4)3

Converting this to log base 10 we have

y=log_10(x+4)/log_10(2)-3y=log10(x+4)log10(2)3

Now this is different as you do have excluded values, in that, from log_10(x+4)log10(x+4)

ul("the values NOT permitted are such that")" "x+4 < 0

So we have permitted value of

color(red)(x>=-4" " ->" Domain"->(-4,oo)

As log_10(2)<1 then log_10(x+4)/log_10(2) > log_10(x+4)

As x tends to infinity then the -3 has very little effect so may be discounted

so color(green)(lim_(x->oo)" "log_10(x+4)/log_10(2)-3=oo" "->"Part of the Range"

When x+4 becomes decimal then log(x+4) becomes negative. The magnitude of the negative number increases the closer to zero (x-4) becomes. Thus :

color(green)(lim_(x+4->0)" "log_10(x+4)/log_10(2)-3= -oo" "->"Part of the range")

color(red)("Range "(-oo,+oo)

Tony BTony B

Apr 10, 2017

See explanation.

Explanation:

The range is the set of all numbers for which the formula is defined.

In this example we have a log_2 function which (as all logarythms) is defined only for positive values, so to calculate the domain we have to solve:

x+4>0

x> -4

So the domain is: D=(-4;+oo)

The log_2 function takes all values, so the range is RR

The asymptote is x=0, because the closer x gets to zero, the smaller is f(x).

lim_{x->0} f(x)=-oo

The graph is:

graph{ log(x+4) - 3 [-6, 30, -17.26, 5.25]}