What is the equation of the line perpendicular to # y=-2/5x-1 # at #x=-1 #?

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Answer 1 · 2017-04-11T11:30:37

#10y = 25 x + 19#

given that #y = -2/5 x - 1#

at #x = -1#
# y = -2/5 (-1) -1 =2/5 -1 = -3/5 #

the line perpendicular has a slope, m where

#m * (-2/5) = -1# #-> m = 5/2#

the equation is,

# y = m x + c# and plug in the values of #x, y and m# to find #c#

#-3/5 = 5/2 *(-1) + c#

#-3/5 = -5/2 + c#

#-3/5 + 5/2 = c# #->19/10 #

therefore the equation is # y = 5/2 x + 19/10# #-> 10y = 25 x + 19#