Question

Question #c83cc

Answer 1

`color(blue)(x=84)`

Explanation:

I'm assuming you mean `-6log_3(x-3)=-24`

Divide both sides by `-6`.

`[1]" "-6log_3(x-3)=-24`

`[2]" "(color(red)(cancel(-6))log_3(x-3))/color(red)(cancel(-6))=(color(red)(cancel(-24))4)/color(red)(cancel(-6))`

`[3]" "log_3(x-3)=4`

We will now change this to its equivalent exponential form. Take note that `y=b^x<=>log_by=x`

`[4]" "<=>3^4=x-3`

`[5]" "81=x-3`

`[6]" "81+3=x`

`[7]" "color(blue)(x=84)`