How do you graph using slope and intercept of #6x + 5y = 2#?

1 Answer
Apr 11, 2017

See below:

Explanation:

First, rewrite it in slope intercept form: #y=mx+b#:

Subtract #6x# on both sides:

#5y=2-6x#

Now divide by #5#

#y=2/5-6/5x#

Rewrite it so the #x# comes first:

#y=-6/5x+2/5#

Now our equation is in the form #y=mx+b#. The #m# which is #-6/5# represents the slope and the #2/5# represents the y-intercept. So make a point on #(0,2/5)# and then move left #6# units of #x# and go up #5# units of #y#. Then, connect the dots:

graph{y=(-6/5)x+(2/5) [-10, 10, -5, 5]}