How do you solve #-8x - 1+ x = 13- 6x - 2#?

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Answer 1 · 2017-04-11T21:17:04

See the entire solution process below:

First, on each side of the equation, combine and group like terms:

#-8x - 1 + x = 12 - 6x - 2#

#-8x + x - 1 = 12 - 2 - 6x#

#-8x + 1x - 1 = 12 - 2 - 6x#

#(-8 + 1)x - 1 = (12 - 2) - 6x#

#-7x - 1 = 10 - 6x#

Next, add #color(red)(7x)# and subtract #color(blue)(10)# from each side of the equation to solve for #x# while keeping the equation balanced:

#-7x - 1 + color(red)(7x) - color(blue)(10) = 10 - 6x + color(red)(7x) - color(blue)(10)#

#-7x + color(red)(7x) - 1 - color(blue)(10) = 10 - color(blue)(10) - 6x + color(red)(7x)#

#0 - 11 = 0 + (-6 + color(red)(7))x#

#-11 = 1x#

#-11 = x#

#x = -11#