What volume of 0.565 M #K_2CO_3# contains exactly 0.115 moles #K_2CO_3#?

1 Answer
David L.
Apr 12, 2017

#V=0.204# #L# or #20.4# #mL#

Explanation:

The units of molarity are #(mol)/(litre)#, using this information, we can solve for the volume.

#L/(0.565 mol)*0.115 mol#

#L/(0.565 cancel(mol))*0.115 cancel(mol)#

#V=0.115/0.565#

#V=0.204# #L# or #20.4# #mL#

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