Question #004f2

1 Answer
Apr 12, 2017

0.56

Explanation:

1 molar solution ="Number of moles of solute"/"Volume of solution"
for Sugar
C_(12)H_(22)O_(11) molar mass=342gm
according to equation and information provided
1=(3.42/342)/x
where x is the volume of solution in l
:. the volume of solution is 0.01 l
which is 10 ml
:.10 gm of water .
moles of solute=3.42/342=0.01
moles of solution =10/18=0.55
:. the mole fraction of the solution is 0.01/(0.01+0.55)