How do you find int(x^2-1/x^2+root3x)dx∫(x2−1x2+3√x)dx?
2 Answers
Explanation:
By rewriting,
By the Power Rule for integration, which states that
By cleaning up,
I hope that this was clear.
Explanation:
integrate each term using the
color(blue)"power rule for integration"power rule for integration
• int(ax^n)=a/(n+1)x^(n+1) ; n!=-1∙∫(axn)=an+1xn+1;n≠−1
rArrint(x^2-1/x^2+root(3)(x))dx⇒∫(x2−1x2+3√x)dx
=int(x^2-x^-2+x^(1/3))larr" in exponent form"=∫(x2−x−2+x13)← in exponent form
=1/3x^3+1/x+3/4x^(4/3)+c=13x3+1x+34x43+c where c is the constant of integration.