How do you show that #1 + tan^2x = sec^2x#?
1 Answer
Apr 13, 2017
Put on a common denominator:
#(cos^2x + sin^2x)/cos^2x= sec^2x#
Use
#1/cos^2x= sec^2x#
Then use
#sec^2x = sec^2x#
This has been proved.
Hopefully this helps!