If #f(x) = (x-6)^2#, what is #f(5)#?

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Answer 1 · 2017-04-14T05:58:20

#1#

Plug #x=5# into the equation:

#f(5)=(5-6)^2#

Then solve:

#f(5)=(-1)^2#

#f(5)=1#

Answer 2 · 2017-04-14T06:04:43

#f(5)=1#

If #f(x)=(x-6)^2#

Then #f(5)# is a point on the line or curve defined by the function equation.

To determine the value of #f(5)#, you need to substitute #5# into the equation for every #x#.

Now; #f(5)=(5-6)^2#

#f(5)=(-1)^2=1#