How do you evaluate #(a^2div4b)+c# given a=12, b=9, c=4?
1 Answer
Apr 14, 2017
Explanation:
#a^2-:4b+c=a^2/(4b)+c#
#"Substitute the given values into the expression"#
#rArr(12)^2/(4xx9)+4#
#=144/36+4#
#=4+4#
#=8#
