Question

How do you find the center and radius for `x^2+(y-3)^2=16`?

Answer 1

See below.

Explanation:

This is a circle, and the standard form is:

`(x-h)^2+(y-k)^2=r^2`, where `(h,k)` is the vertex, and `r` is the radius.

The equation you want can be rewritten as:
`(x-0)^2+(y-3)^2=4^2`

So, the center is `(0,3)`, and the radius is `4`.