Question

Question #6ad49

Answer 1

`log6^(1/3)`

Explanation:

Using the `color(blue)"law of logarithms"`

`color(red)(bar(ul(|color(white)(2/2)color(black)(logx^nhArrnlogx)color(white)(2/2)|)))`

`rArr(log6)/3=1/3log6=log6^(1/3)`

Answer 2

Please see the explanation.

Explanation:

Given: `(log(6))/3`

The above can be written as:

`(1/3)log(6)`

Use the property of logarithms `(c)log(a) = log(a^c)`:

`log(6^(1/3))`

We know that the `1/3` power is the same as the cube root:

`log(root3(6)) larr` the answer.