How do you simplify #((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)#?

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Answer 1 · 2017-04-15T20:01:02

#((2p-1)^2)/((p+1))#

This is just a question of knowing your indice laws.

#((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)#

When there is a division of indices with the same base, the indices are subtracted.

For #(p+1)#, it is #1-2 = -1#, therefore the (p+1) on the numerator disappears and the one on the denominator stays.

#((2p-1)^4)/((p+1)(2p-1)^2)#

For #(2p-1)#, it is #4-2=2#, therefore the #(2p-1)# on the denominator disappears and the one on the numerator stays.

#((2p-1)^2)/((p+1))#