How do you simplify #(1/4)(-9)(1/5)#?
1 Answer
Apr 16, 2017
Explanation:
We can consider this to be the multiplication of 3 fractions.
#"That is "#
#1/4xx(-9)/1xx1/5#
#"there is no "color(blue)"cancelling" " between numerator/denominator"#
#"Hence multiply remaining values on numerator/denominator"#
#rArr(1xx-9xx1)/(4xx1xx5)#
#=(-9)/20#
#=-9/20larrcolor(red)" in simplest form"#
