How do you solve #-5y - \frac{2}{3} = \frac{2}{3} y - \frac{7}{2}#?

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Answer 1 · 2017-04-16T18:31:46

#y = 1/2#

If you have an equation which has fractions you can get rid of the fractions immediately by multiplying by the LCD to cancel the denominators.

#color(blue)(6xx-5y)-(color(blue)(cancel6^2xx2))/cancel3 = (color(blue)(cancel6^2xx2))/cancel3y-(color(blue)(cancel6^3xx7))/cancel2#

#-30y -4=4y-21#

Move the like terms to the same side, making #y# positive.

#21-4 = 4y -30y#

#17 = 34y" "larr div 34#

#17/34 =y#