How do you solve the system of equations #-x - 6y = - 10# and #x + 9y = 16#?

1 Answer
Alberto M.
Apr 17, 2017

#(-2,2)#

Explanation:

You can go with substitution:
the second equation gives #x=16-9y#, so substituting in the first:
#-16+9y-6y=-10#, so #3y=6 Rightarrow y=2#, and putting #y=2# in the second equation we get #x=-2#

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