Question

Question #6ec6f

Answer 1

The mass % or `w/w` % of the `H_2SO_4` solution is `29%`
This means `100` g of the solution contains `29` g or `(29g)/(98g"/"mol)=29/98 mol` `H_2SO_4`.
Now let the density of the solution be `d` `g"/"mL`

So volume of 100 g `H_2SO_4` solution is `100/d` mL or
`0.1/d` L

So molarity of the solution is `(29/98)/(0.1/d)` M

So by the problem

`(29/98)/(0.1/d)=3.6`

`=>d =(3.6xx9.8)/29~~1.2` `g"/"mL`