What is the standard form of # y= (4x-4)(6x-2)(1/8x-1/4)#?

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Answer 1 · 2017-04-18T12:49:17

#3x^3-10x^2+9x-2#

When you multiply the first two parts of the equation you will get:

#y=(24x^2-8x-24x+8)((x/8)-(1/4))#

Now you can arrange it:

#y=(24x^2-32x+8)((x/8)-(1/4))#

Multiply terms again:

#y=3x^3-6x^2-4x^2+8x+x-2#

Arrange the above equation:

#y=3x^3-10x^2+9x-2#

This is the answer.