What is the concentration of an #18.9g# mass of ammonium nitrate dissolved in an #855mL# volume of solution?

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Answer 1 · 2017-04-18T18:12:58

#"Molarity"-="Moles of solute"/"Volume of solution"-=0.276*mol*L^-1#.

#"Molarity"=((18.9*g)/(80.05*g*mol^-1))/(0.855*L)=0.276*mol*L^-1#.

And all we did here was to apply the definition of #"molarity"#, i.e. #"moles of solute per unit volume of solution"#.

Would this solution be slightly acidic or slightly basic........?

What is the concentration of an #18.9*g# mass of ammonium nitrate dissolved in an #855*mL# volume of solution?